Natural Deduction elimination of disjunction

The first $(\vee E)$ we present is an indirect rule. We can eliminate a dis-junction $A\vee B$ by showing that some formula $C$ follows from both $A$ and $B$, so whichever of $A$ or $B$ is the case, $C$ will hold: ?

$$\frac{A\to C,B\to C,A\vee B}{C}(\vee E)$$